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12660469793 is a prime number
BaseRepresentation
bin10111100101001111…
…10111000000100001
31012200022220111120122
423302213313000201
5201412040013133
65452141450025
7625511134436
oct136247670041
935608814518
1012660469793
115407561384
122553b70915
131269c4315a
14881625b8d
154e1735498
hex2f29f7021

12660469793 has 2 divisors, whose sum is σ = 12660469794. Its totient is φ = 12660469792.

The previous prime is 12660469751. The next prime is 12660469813. The reversal of 12660469793 is 39796406621.

12660469793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6974254144 + 5686215649 = 83512^2 + 75407^2 .

It is an emirp because it is prime and its reverse (39796406621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12660469793 - 28 = 12660469537 is a prime.

It is not a weakly prime, because it can be changed into another prime (12660469733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6330234896 + 6330234897.

It is an arithmetic number, because the mean of its divisors is an integer number (6330234897).

Almost surely, 212660469793 is an apocalyptic number.

It is an amenable number.

12660469793 is a deficient number, since it is larger than the sum of its proper divisors (1).

12660469793 is an equidigital number, since it uses as much as digits as its factorization.

12660469793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2939328, while the sum is 53.

The spelling of 12660469793 in words is "twelve billion, six hundred sixty million, four hundred sixty-nine thousand, seven hundred ninety-three".