Base | Representation |
---|---|
bin | 10010011011001000001… |
… | …010001011000101111111 |
3 | 11111000222012001110102221 |
4 | 102123020022023011333 |
5 | 131220412043320403 |
6 | 2405343424030211 |
7 | 160320414433552 |
oct | 22331012130577 |
9 | 4430865043387 |
10 | 1266078495103 |
11 | 448a39338524 |
12 | 18545b162367 |
13 | 92510465056 |
14 | 453c83c0699 |
15 | 22e00dcddbd |
hex | 126c828b17f |
1266078495103 has 2 divisors, whose sum is σ = 1266078495104. Its totient is φ = 1266078495102.
The previous prime is 1266078495067. The next prime is 1266078495127. The reversal of 1266078495103 is 3015948706621.
It is a strong prime.
It is an emirp because it is prime and its reverse (3015948706621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1266078495103 - 233 = 1257488560511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1266078495173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 633039247551 + 633039247552.
It is an arithmetic number, because the mean of its divisors is an integer number (633039247552).
It is a 1-persistent number, because it is pandigital, but 2⋅1266078495103 = 2532156990206 is not.
Almost surely, 21266078495103 is an apocalyptic number.
1266078495103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1266078495103 is an equidigital number, since it uses as much as digits as its factorization.
1266078495103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 52.
The spelling of 1266078495103 in words is "one trillion, two hundred sixty-six billion, seventy-eight million, four hundred ninety-five thousand, one hundred three".
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