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12663880425143 = 13999052094657
BaseRepresentation
bin1011100001001000101000…
…0110000001111010110111
31122211122200121012222121122
42320102022012001322313
53124441111342101033
642533412323334155
72444635522351043
oct270221206017267
948748617188548
1012663880425143
1140427a3398292
121506417b2135b
1370b2779c040c
1431ad13c21023
1516e63aee6a98
hexb848a181eb7

12663880425143 has 4 divisors (see below), whose sum is σ = 12672932521200. Its totient is φ = 12654828329088.

The previous prime is 12663880425137. The next prime is 12663880425167. The reversal of 12663880425143 is 34152408836621.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12663880425143 - 212 = 12663880421047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12668880425143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4526045930 + ... + 4526048727.

It is an arithmetic number, because the mean of its divisors is an integer number (3168233130300).

Almost surely, 212663880425143 is an apocalyptic number.

12663880425143 is a deficient number, since it is larger than the sum of its proper divisors (9052096057).

12663880425143 is an equidigital number, since it uses as much as digits as its factorization.

12663880425143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9052096056.

The product of its (nonzero) digits is 6635520, while the sum is 53.

The spelling of 12663880425143 in words is "twelve trillion, six hundred sixty-three billion, eight hundred eighty million, four hundred twenty-five thousand, one hundred forty-three".

Divisors: 1 1399 9052094657 12663880425143