12667141011253 has 2 divisors, whose sum is σ = 12667141011254. Its totient is φ = 12667141011252.

The previous prime is 12667141011227. The next prime is 12667141011307. The reversal of 12667141011253 is 35211014176621.

12667141011253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9780737091889 + 2886403919364 = 3127417^2 + 1698942^2 .

It is an emirp because it is prime and its reverse (35211014176621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12667141011253 - 2²⁵ = 12667107456821 is a prime.

It is a super-2 number, since 2×12667141011253² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12667141011653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6333570505626 + 6333570505627.

It is an arithmetic number, because the mean of its divisors is an integer number (6333570505627).

Almost surely, 2^{12667141011253} is an apocalyptic number.

It is an amenable number.

12667141011253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12667141011253 is an equidigital number, since it uses as much as digits as its factorization.

12667141011253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 40.

Adding to 12667141011253 its reverse (35211014176621), we get a palindrome (47878155187874).

The spelling of 12667141011253 in words is "twelve trillion, six hundred sixty-seven billion, one hundred forty-one million, eleven thousand, two hundred fifty-three".