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12669494941 is a prime number
BaseRepresentation
bin10111100110010100…
…10010011010011101
31012200221220000202101
423303022102122131
5201421342314231
65453103125101
7625650634015
oct136312223235
935627800671
1012669494941
115411666084
122556ba3791
13126ba8308c
148828d4c45
154e2419661
hex2f329269d

12669494941 has 2 divisors, whose sum is σ = 12669494942. Its totient is φ = 12669494940.

The previous prime is 12669494927. The next prime is 12669494947. The reversal of 12669494941 is 14949496621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12668402916 + 1092025 = 112554^2 + 1045^2 .

It is an emirp because it is prime and its reverse (14949496621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12669494941 - 217 = 12669363869 is a prime.

It is a super-3 number, since 3×126694949413 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12669494947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6334747470 + 6334747471.

It is an arithmetic number, because the mean of its divisors is an integer number (6334747471).

Almost surely, 212669494941 is an apocalyptic number.

It is an amenable number.

12669494941 is a deficient number, since it is larger than the sum of its proper divisors (1).

12669494941 is an equidigital number, since it uses as much as digits as its factorization.

12669494941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3359232, while the sum is 55.

The spelling of 12669494941 in words is "twelve billion, six hundred sixty-nine million, four hundred ninety-four thousand, nine hundred forty-one".