Base | Representation |
---|---|
bin | 1011100001100100110111… |
… | …0101010010011101011111 |
3 | 1122212101020210021122122202 |
4 | 2320121031311102131133 |
5 | 3130102122042304304 |
6 | 42541104342002115 |
7 | 2445324401142113 |
oct | 270311565223537 |
9 | 48771223248582 |
10 | 12671459338079 |
11 | 4045a324a77a3 |
12 | 150799211633b |
13 | 70bbb4c1aa99 |
14 | 31b4325d5743 |
15 | 16e93156581e |
hex | b864dd5275f |
12671459338079 has 2 divisors, whose sum is σ = 12671459338080. Its totient is φ = 12671459338078.
The previous prime is 12671459338067. The next prime is 12671459338117. The reversal of 12671459338079 is 97083395417621.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12671459338079 - 24 = 12671459338063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12671459338019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6335729669039 + 6335729669040.
It is an arithmetic number, because the mean of its divisors is an integer number (6335729669040).
It is a 1-persistent number, because it is pandigital, but 2⋅12671459338079 = 25342918676158 is not.
Almost surely, 212671459338079 is an apocalyptic number.
12671459338079 is a deficient number, since it is larger than the sum of its proper divisors (1).
12671459338079 is an equidigital number, since it uses as much as digits as its factorization.
12671459338079 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68584320, while the sum is 65.
The spelling of 12671459338079 in words is "twelve trillion, six hundred seventy-one billion, four hundred fifty-nine million, three hundred thirty-eight thousand, seventy-nine".
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