Base | Representation |
---|---|
bin | 1011100010010001100101… |
… | …1000001010110001111111 |
3 | 1122220112020102112101002211 |
4 | 2320210121120022301333 |
5 | 3130301213313103403 |
6 | 42550411503401251 |
7 | 2446231031540446 |
oct | 270443130126177 |
9 | 48815212471084 |
10 | 12683464191103 |
11 | 4050032973532 |
12 | 150a1825b3227 |
13 | 710079091504 |
14 | 31bc50b17d5d |
15 | 16edd544406d |
hex | b891960ac7f |
12683464191103 has 2 divisors, whose sum is σ = 12683464191104. Its totient is φ = 12683464191102.
The previous prime is 12683464191089. The next prime is 12683464191143. The reversal of 12683464191103 is 30119146438621.
12683464191103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12683464191103 - 237 = 12546025237631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12683464191143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6341732095551 + 6341732095552.
It is an arithmetic number, because the mean of its divisors is an integer number (6341732095552).
Almost surely, 212683464191103 is an apocalyptic number.
12683464191103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12683464191103 is an equidigital number, since it uses as much as digits as its factorization.
12683464191103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 746496, while the sum is 49.
The spelling of 12683464191103 in words is "twelve trillion, six hundred eighty-three billion, four hundred sixty-four million, one hundred ninety-one thousand, one hundred three".
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