Base | Representation |
---|---|
bin | 10111101000101001… |
… | …00100100110011011 |
3 | 1012202022112100220011 |
4 | 23310110210212123 |
5 | 201441333434331 |
6 | 5455040342351 |
7 | 626305310032 |
oct | 136424444633 |
9 | 35668470804 |
10 | 12688968091 |
11 | 5421656598 |
12 | 25616149b7 |
13 | 1272b10757 |
14 | 885323719 |
15 | 4e3eb43b1 |
hex | 2f452499b |
12688968091 has 4 divisors (see below), whose sum is σ = 12695356072. Its totient is φ = 12682580112.
The previous prime is 12688968043. The next prime is 12688968161. The reversal of 12688968091 is 19086988621.
12688968091 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12688968091 - 29 = 12688967579 is a prime.
It is a super-2 number, since 2×126889680912 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12688968001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3191010 + ... + 3194983.
It is an arithmetic number, because the mean of its divisors is an integer number (3173839018).
Almost surely, 212688968091 is an apocalyptic number.
12688968091 is a deficient number, since it is larger than the sum of its proper divisors (6387981).
12688968091 is an equidigital number, since it uses as much as digits as its factorization.
12688968091 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6387980.
The product of its (nonzero) digits is 2985984, while the sum is 58.
The spelling of 12688968091 in words is "twelve billion, six hundred eighty-eight million, nine hundred sixty-eight thousand, ninety-one".
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