Base | Representation |
---|---|
bin | 1011100010111010110111… |
… | …0100101110011111110101 |
3 | 1122221120211122100111110121 |
4 | 2320232231310232133311 |
5 | 3130441411411434424 |
6 | 42555443204051541 |
7 | 2450102436026242 |
oct | 270565564563765 |
9 | 48846748314417 |
10 | 12694544639989 |
11 | 40547a9559803 |
12 | 1510355393bb1 |
13 | 711123875644 |
14 | 31c5c256a5c9 |
15 | 1703330c4ee4 |
hex | b8badd2e7f5 |
12694544639989 has 2 divisors, whose sum is σ = 12694544639990. Its totient is φ = 12694544639988.
The previous prime is 12694544639941. The next prime is 12694544640023. The reversal of 12694544639989 is 98993644549621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9216476298225 + 3478068341764 = 3035865^2 + 1864958^2 .
It is a cyclic number.
It is not a de Polignac number, because 12694544639989 - 211 = 12694544637941 is a prime.
It is a super-3 number, since 3×126945446399893 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12694544639089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6347272319994 + 6347272319995.
It is an arithmetic number, because the mean of its divisors is an integer number (6347272319995).
Almost surely, 212694544639989 is an apocalyptic number.
It is an amenable number.
12694544639989 is a deficient number, since it is larger than the sum of its proper divisors (1).
12694544639989 is an equidigital number, since it uses as much as digits as its factorization.
12694544639989 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3627970560, while the sum is 79.
The spelling of 12694544639989 in words is "twelve trillion, six hundred ninety-four billion, five hundred forty-four million, six hundred thirty-nine thousand, nine hundred eighty-nine".
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