12699211307 has 2 divisors, whose sum is σ = 12699211308. Its totient is φ = 12699211306.

The previous prime is 12699211277. The next prime is 12699211309. The reversal of 12699211307 is 70311299621.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12699211307 - 2¹⁸ = 12698949163 is a prime.

It is a super-2 number, since 2×12699211307² (a number of 21 digits) contains 22 as substring.

Together with 12699211309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12699211309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6349605653 + 6349605654.

It is an arithmetic number, because the mean of its divisors is an integer number (6349605654).

Almost surely, 2^12699211307 is an apocalyptic number.

12699211307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12699211307 is an equidigital number, since it uses as much as digits as its factorization.

12699211307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40824, while the sum is 41.

The spelling of 12699211307 in words is "twelve billion, six hundred ninety-nine million, two hundred eleven thousand, three hundred seven".