Base | Representation |
---|---|
bin | 10111101001111010… |
… | …00101101101011111 |
3 | 1012210001111222200121 |
4 | 23310331011231133 |
5 | 202002043330341 |
6 | 5500100135411 |
7 | 626464505122 |
oct | 136475055537 |
9 | 35701458617 |
10 | 12699589471 |
11 | 5427650598 |
12 | 2565097567 |
13 | 127508c0aa |
14 | 8868ca3b9 |
15 | 4e4db14d1 |
hex | 2f4f45b5f |
12699589471 has 2 divisors, whose sum is σ = 12699589472. Its totient is φ = 12699589470.
The previous prime is 12699589429. The next prime is 12699589501. The reversal of 12699589471 is 17498599621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12699589471 - 215 = 12699556703 is a prime.
It is a super-3 number, since 3×126995894713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12699539471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6349794735 + 6349794736.
It is an arithmetic number, because the mean of its divisors is an integer number (6349794736).
Almost surely, 212699589471 is an apocalyptic number.
12699589471 is a deficient number, since it is larger than the sum of its proper divisors (1).
12699589471 is an equidigital number, since it uses as much as digits as its factorization.
12699589471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9797760, while the sum is 61.
The spelling of 12699589471 in words is "twelve billion, six hundred ninety-nine million, five hundred eighty-nine thousand, four hundred seventy-one".
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