Base | Representation |
---|---|
bin | 10010011110110010000… |
… | …111111100001000000011 |
3 | 11111102002202011111100212 |
4 | 102132302013330020003 |
5 | 131301431431344201 |
6 | 2411233124304335 |
7 | 160516606666301 |
oct | 22366207741003 |
9 | 4442082144325 |
10 | 1270003778051 |
11 | 44a673029718 |
12 | 1861758420ab |
13 | 929b7755b98 |
14 | 4567b845271 |
15 | 230807e5abb |
hex | 127b21fc203 |
1270003778051 has 2 divisors, whose sum is σ = 1270003778052. Its totient is φ = 1270003778050.
The previous prime is 1270003778039. The next prime is 1270003778053. The reversal of 1270003778051 is 1508773000721.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1270003778051 is a prime.
It is a super-2 number, since 2×12700037780512 (a number of 25 digits) contains 22 as substring.
Together with 1270003778053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1270003778053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 635001889025 + 635001889026.
It is an arithmetic number, because the mean of its divisors is an integer number (635001889026).
Almost surely, 21270003778051 is an apocalyptic number.
1270003778051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1270003778051 is an equidigital number, since it uses as much as digits as its factorization.
1270003778051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82320, while the sum is 41.
Adding to 1270003778051 its reverse (1508773000721), we get a palindrome (2778776778772).
The spelling of 1270003778051 in words is "one trillion, two hundred seventy billion, three million, seven hundred seventy-eight thousand, fifty-one".
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