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12701471325247 is a prime number
BaseRepresentation
bin1011100011010100101010…
…1011111011110000111111
31122222020201101010120100001
42320311022223323300333
53131100103124401442
643002550403015131
72450436204625015
oct270651253736077
948866641116301
1012701471325247
114057733488981
12151176906a4a7
1371198891c083
1431ca7c4808b5
151705db25b2b7
hexb8d4aafbc3f

12701471325247 has 2 divisors, whose sum is σ = 12701471325248. Its totient is φ = 12701471325246.

The previous prime is 12701471325211. The next prime is 12701471325281. The reversal of 12701471325247 is 74252317410721.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12701471325247 - 211 = 12701471323199 is a prime.

It is a super-2 number, since 2×127014713252472 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12701471325197 and 12701471325206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12701471325847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6350735662623 + 6350735662624.

It is an arithmetic number, because the mean of its divisors is an integer number (6350735662624).

Almost surely, 212701471325247 is an apocalyptic number.

12701471325247 is a deficient number, since it is larger than the sum of its proper divisors (1).

12701471325247 is an equidigital number, since it uses as much as digits as its factorization.

12701471325247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 658560, while the sum is 46.

Adding to 12701471325247 its reverse (74252317410721), we get a palindrome (86953788735968).

The spelling of 12701471325247 in words is "twelve trillion, seven hundred one billion, four hundred seventy-one million, three hundred twenty-five thousand, two hundred forty-seven".