Base | Representation |
---|---|
bin | 1011100011010110101111… |
… | …1111010100010111010111 |
3 | 1122222022011022110222021211 |
4 | 2320311223333110113113 |
5 | 3131102224143223441 |
6 | 43003122042322251 |
7 | 2450456101015243 |
oct | 270655377242727 |
9 | 48868138428254 |
10 | 12702030054871 |
11 | 405799a9087a3 |
12 | 15118a41b9387 |
13 | 711a475c7b11 |
14 | 31cad2763423 |
15 | 170620325a81 |
hex | b8d6bfd45d7 |
12702030054871 has 2 divisors, whose sum is σ = 12702030054872. Its totient is φ = 12702030054870.
The previous prime is 12702030054851. The next prime is 12702030054881. The reversal of 12702030054871 is 17845003020721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12702030054871 - 27 = 12702030054743 is a prime.
It is a super-2 number, since 2×127020300548712 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12702030054821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6351015027435 + 6351015027436.
It is an arithmetic number, because the mean of its divisors is an integer number (6351015027436).
Almost surely, 212702030054871 is an apocalyptic number.
12702030054871 is a deficient number, since it is larger than the sum of its proper divisors (1).
12702030054871 is an equidigital number, since it uses as much as digits as its factorization.
12702030054871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94080, while the sum is 40.
The spelling of 12702030054871 in words is "twelve trillion, seven hundred two billion, thirty million, fifty-four thousand, eight hundred seventy-one".
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