127115113 has 2 divisors, whose sum is σ = 127115114. Its totient is φ = 127115112.

The previous prime is 127115101. The next prime is 127115117. The reversal of 127115113 is 311511721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73136704 + 53978409 = 8552^2 + 7347^2 .

It is an emirp because it is prime and its reverse (311511721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 127115113 - 2¹³ = 127106921 is a prime.

It is not a weakly prime, because it can be changed into another prime (127115117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63557556 + 63557557.

It is an arithmetic number, because the mean of its divisors is an integer number (63557557).

Almost surely, 2^127115113 is an apocalyptic number.

It is an amenable number.

127115113 is a deficient number, since it is larger than the sum of its proper divisors (1).

127115113 is an equidigital number, since it uses as much as digits as its factorization.

127115113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 210, while the sum is 22.

The square root of 127115113 is about 11274.5338262830. The cubic root of 127115113 is about 502.8043920301.

Adding to 127115113 its reverse (311511721), we get a palindrome (438626834).

It can be divided in two parts, 1271 and 15113, that added together give a 14-th power (16384 = 2¹⁴).

The spelling of 127115113 in words is "one hundred twenty-seven million, one hundred fifteen thousand, one hundred thirteen".