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12714803113 = 31740109789
BaseRepresentation
bin10111101011101110…
…00111111110101001
31012211010010220212211
423311313013332221
5202014442144423
65501402205121
7630041020555
oct136567077651
935733126784
1012714803113
1154351a1851
12256a1b37a1
131278287a4c
1488892a865
154e63b910d
hex2f5dc7fa9

12714803113 has 4 divisors (see below), whose sum is σ = 12754913220. Its totient is φ = 12674693008.

The previous prime is 12714803089. The next prime is 12714803119. The reversal of 12714803113 is 31130841721.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3778315024 + 8936488089 = 61468^2 + 94533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12714803113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12714803119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20054578 + ... + 20055211.

It is an arithmetic number, because the mean of its divisors is an integer number (3188728305).

Almost surely, 212714803113 is an apocalyptic number.

It is an amenable number.

12714803113 is a deficient number, since it is larger than the sum of its proper divisors (40110107).

12714803113 is an equidigital number, since it uses as much as digits as its factorization.

12714803113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40110106.

The product of its (nonzero) digits is 4032, while the sum is 31.

The spelling of 12714803113 in words is "twelve billion, seven hundred fourteen million, eight hundred three thousand, one hundred thirteen".

Divisors: 1 317 40109789 12714803113