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12718821645853 is a prime number
BaseRepresentation
bin1011100100010101010011…
…0110001001111000011101
31200000220111112211011202221
42321011110312021320131
53131341121320131403
643014540200345341
72451622154130061
oct271052466117035
950026445734687
1012718821645853
114064027270614
121514bab775251
137134c237b57b
1431d8468b1aa1
15170ca4581dbd
hexb9154d89e1d

12718821645853 has 2 divisors, whose sum is σ = 12718821645854. Its totient is φ = 12718821645852.

The previous prime is 12718821645841. The next prime is 12718821645869. The reversal of 12718821645853 is 35854612881721.

12718821645853 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12289918467204 + 428903178649 = 3505698^2 + 654907^2 .

It is a cyclic number.

It is not a de Polignac number, because 12718821645853 - 237 = 12581382692381 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12718821645791 and 12718821645800.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12718821645823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6359410822926 + 6359410822927.

It is an arithmetic number, because the mean of its divisors is an integer number (6359410822927).

Almost surely, 212718821645853 is an apocalyptic number.

It is an amenable number.

12718821645853 is a deficient number, since it is larger than the sum of its proper divisors (1).

12718821645853 is an equidigital number, since it uses as much as digits as its factorization.

12718821645853 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25804800, while the sum is 61.

The spelling of 12718821645853 in words is "twelve trillion, seven hundred eighteen billion, eight hundred twenty-one million, six hundred forty-five thousand, eight hundred fifty-three".