Base | Representation |
---|---|
bin | 10111101100010101… |
… | …01100100001000101 |
3 | 1012211110210120110111 |
4 | 23312022230201011 |
5 | 202022300333014 |
6 | 5502104153021 |
7 | 630132436153 |
oct | 136612544105 |
9 | 35743716414 |
10 | 12719933509 |
11 | 5438086348 |
12 | 256ba68771 |
13 | 1279362c9a |
14 | 8894a43d3 |
15 | 4e6a7e2c4 |
hex | 2f62ac845 |
12719933509 has 2 divisors, whose sum is σ = 12719933510. Its totient is φ = 12719933508.
The previous prime is 12719933497. The next prime is 12719933533. The reversal of 12719933509 is 90533991721.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10520604900 + 2199328609 = 102570^2 + 46897^2 .
It is a cyclic number.
It is not a de Polignac number, because 12719933509 - 219 = 12719409221 is a prime.
It is a super-4 number, since 4×127199335094 (a number of 42 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12719933309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6359966754 + 6359966755.
It is an arithmetic number, because the mean of its divisors is an integer number (6359966755).
Almost surely, 212719933509 is an apocalyptic number.
It is an amenable number.
12719933509 is a deficient number, since it is larger than the sum of its proper divisors (1).
12719933509 is an equidigital number, since it uses as much as digits as its factorization.
12719933509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 459270, while the sum is 49.
The spelling of 12719933509 in words is "twelve billion, seven hundred nineteen million, nine hundred thirty-three thousand, five hundred nine".
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