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1272100404143 is a prime number
BaseRepresentation
bin10010100000101111000…
…101111011101110101111
311111121111212100010200002
4102200233011323232233
5131320230200413033
62412221142254515
7160622556011642
oct22405705735657
94447455303602
101272100404143
11450549572958
1218665ba2743b
1392c5cc3213a
14457da093a59
15231548e33e8
hex1282f17bbaf

1272100404143 has 2 divisors, whose sum is σ = 1272100404144. Its totient is φ = 1272100404142.

The previous prime is 1272100404139. The next prime is 1272100404149. The reversal of 1272100404143 is 3414040012721.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1272100404143 - 22 = 1272100404139 is a prime.

It is a super-3 number, since 3×12721004041433 (a number of 37 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1272100404149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 636050202071 + 636050202072.

It is an arithmetic number, because the mean of its divisors is an integer number (636050202072).

Almost surely, 21272100404143 is an apocalyptic number.

1272100404143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1272100404143 is an equidigital number, since it uses as much as digits as its factorization.

1272100404143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 1272100404143 its reverse (3414040012721), we get a palindrome (4686140416864).

The spelling of 1272100404143 in words is "one trillion, two hundred seventy-two billion, one hundred million, four hundred four thousand, one hundred forty-three".