Base | Representation |
---|---|
bin | 111011001111001010… |
… | …0000111001101010101 |
3 | 110011100111021212101102 |
4 | 1312132110013031111 |
5 | 4041011242432432 |
6 | 134234534235445 |
7 | 12122246133266 |
oct | 1663624071525 |
9 | 404314255342 |
10 | 127210124117 |
11 | 49a4988708a |
12 | 207a24b5b85 |
13 | bcc3bb07bb |
14 | 622ab5c96d |
15 | 3497e78962 |
hex | 1d9e507355 |
127210124117 has 2 divisors, whose sum is σ = 127210124118. Its totient is φ = 127210124116.
The previous prime is 127210124099. The next prime is 127210124179. The reversal of 127210124117 is 711421012721.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114058851076 + 13151273041 = 337726^2 + 114679^2 .
It is a cyclic number.
It is not a de Polignac number, because 127210124117 - 28 = 127210123861 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 127210124117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (127210124417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63605062058 + 63605062059.
It is an arithmetic number, because the mean of its divisors is an integer number (63605062059).
Almost surely, 2127210124117 is an apocalyptic number.
It is an amenable number.
127210124117 is a deficient number, since it is larger than the sum of its proper divisors (1).
127210124117 is an equidigital number, since it uses as much as digits as its factorization.
127210124117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1568, while the sum is 29.
Adding to 127210124117 its reverse (711421012721), we get a palindrome (838631136838).
The spelling of 127210124117 in words is "one hundred twenty-seven billion, two hundred ten million, one hundred twenty-four thousand, one hundred seventeen".
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