Base | Representation |
---|---|
bin | 1011100101000000100001… |
… | …1111010010100001000101 |
3 | 1200002000110020111022010022 |
4 | 2321100020133102201011 |
5 | 3132033402411013011 |
6 | 43024135435104525 |
7 | 2452512545133032 |
oct | 271201037224105 |
9 | 50060406438108 |
10 | 12730425485381 |
11 | 4068a41339a3a |
12 | 15172a98a2145 |
13 | 7146214172c6 |
14 | 320227a48389 |
15 | 17123314b8db |
hex | b94087d2845 |
12730425485381 has 2 divisors, whose sum is σ = 12730425485382. Its totient is φ = 12730425485380.
The previous prime is 12730425485357. The next prime is 12730425485399. The reversal of 12730425485381 is 18358452403721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7034880952225 + 5695544533156 = 2652335^2 + 2386534^2 .
It is a cyclic number.
It is not a de Polignac number, because 12730425485381 - 238 = 12455547578437 is a prime.
It is a super-2 number, since 2×127304254853812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12730425485341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6365212742690 + 6365212742691.
It is an arithmetic number, because the mean of its divisors is an integer number (6365212742691).
Almost surely, 212730425485381 is an apocalyptic number.
It is an amenable number.
12730425485381 is a deficient number, since it is larger than the sum of its proper divisors (1).
12730425485381 is an equidigital number, since it uses as much as digits as its factorization.
12730425485381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6451200, while the sum is 53.
The spelling of 12730425485381 in words is "twelve trillion, seven hundred thirty billion, four hundred twenty-five million, four hundred eighty-five thousand, three hundred eighty-one".
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