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12730425485381 is a prime number
BaseRepresentation
bin1011100101000000100001…
…1111010010100001000101
31200002000110020111022010022
42321100020133102201011
53132033402411013011
643024135435104525
72452512545133032
oct271201037224105
950060406438108
1012730425485381
114068a41339a3a
1215172a98a2145
137146214172c6
14320227a48389
1517123314b8db
hexb94087d2845

12730425485381 has 2 divisors, whose sum is σ = 12730425485382. Its totient is φ = 12730425485380.

The previous prime is 12730425485357. The next prime is 12730425485399. The reversal of 12730425485381 is 18358452403721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7034880952225 + 5695544533156 = 2652335^2 + 2386534^2 .

It is a cyclic number.

It is not a de Polignac number, because 12730425485381 - 238 = 12455547578437 is a prime.

It is a super-2 number, since 2×127304254853812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12730425485341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6365212742690 + 6365212742691.

It is an arithmetic number, because the mean of its divisors is an integer number (6365212742691).

Almost surely, 212730425485381 is an apocalyptic number.

It is an amenable number.

12730425485381 is a deficient number, since it is larger than the sum of its proper divisors (1).

12730425485381 is an equidigital number, since it uses as much as digits as its factorization.

12730425485381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6451200, while the sum is 53.

The spelling of 12730425485381 in words is "twelve trillion, seven hundred thirty billion, four hundred twenty-five million, four hundred eighty-five thousand, three hundred eighty-one".