Base | Representation |
---|---|
bin | 10111101101110010… |
… | …00101000000100001 |
3 | 1012212022200022101121 |
4 | 23312321011000201 |
5 | 202033403424244 |
6 | 5503220532241 |
7 | 630341000026 |
oct | 136671050041 |
9 | 35768608347 |
10 | 12732092449 |
11 | 5443a3055a |
12 | 2573b51081 |
13 | 127ba2c41b |
14 | 88ad4b54d |
15 | 4e7b81c84 |
hex | 2f6e45021 |
12732092449 has 4 divisors (see below), whose sum is σ = 12758236864. Its totient is φ = 12705948036.
The previous prime is 12732092441. The next prime is 12732092473. The reversal of 12732092449 is 94429023721.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 94429023721 = 23 ⋅4105609727.
It is a cyclic number.
It is not a de Polignac number, because 12732092449 - 23 = 12732092441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12732092441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13071477 + ... + 13072450.
It is an arithmetic number, because the mean of its divisors is an integer number (3189559216).
Almost surely, 212732092449 is an apocalyptic number.
It is an amenable number.
12732092449 is a deficient number, since it is larger than the sum of its proper divisors (26144415).
12732092449 is an equidigital number, since it uses as much as digits as its factorization.
12732092449 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26144414.
The product of its (nonzero) digits is 217728, while the sum is 43.
The spelling of 12732092449 in words is "twelve billion, seven hundred thirty-two million, ninety-two thousand, four hundred forty-nine".
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