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12732183536741 is a prime number
BaseRepresentation
bin1011100101000111000101…
…0001101110010001100101
31200002011222202120120012122
42321101301101232101211
53132101002441133431
643025030120155325
72452604243255144
oct271216121562145
950064882516178
1012732183536741
114069763751a49
1215176ba608b45
1371484170a896
1432035332175b
151712d766aa7b
hexb947146e465

12732183536741 has 2 divisors, whose sum is σ = 12732183536742. Its totient is φ = 12732183536740.

The previous prime is 12732183536717. The next prime is 12732183536747. The reversal of 12732183536741 is 14763538123721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10282629875716 + 2449553661025 = 3206654^2 + 1565105^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12732183536741 is a prime.

It is a super-2 number, since 2×127321835367412 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12732183536747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6366091768370 + 6366091768371.

It is an arithmetic number, because the mean of its divisors is an integer number (6366091768371).

Almost surely, 212732183536741 is an apocalyptic number.

It is an amenable number.

12732183536741 is a deficient number, since it is larger than the sum of its proper divisors (1).

12732183536741 is an equidigital number, since it uses as much as digits as its factorization.

12732183536741 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5080320, while the sum is 53.

The spelling of 12732183536741 in words is "twelve trillion, seven hundred thirty-two billion, one hundred eighty-three million, five hundred thirty-six thousand, seven hundred forty-one".