Base | Representation |
---|---|
bin | 10010100010000001100… |
… | …001001000000010101011 |
3 | 11111202002020102201000011 |
4 | 102202001201020002223 |
5 | 131331043203423141 |
6 | 2413010301552351 |
7 | 161002050066556 |
oct | 22420141100253 |
9 | 4452066381004 |
10 | 1273483264171 |
11 | 451099115088 |
12 | 186986b756b7 |
13 | 9312058c201 |
14 | 458cb9c369d |
15 | 231d5eee881 |
hex | 128818480ab |
1273483264171 has 2 divisors, whose sum is σ = 1273483264172. Its totient is φ = 1273483264170.
The previous prime is 1273483264127. The next prime is 1273483264187. The reversal of 1273483264171 is 1714623843721.
It is a strong prime.
It is an emirp because it is prime and its reverse (1714623843721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1273483264171 - 217 = 1273483133099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1273483264871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 636741632085 + 636741632086.
It is an arithmetic number, because the mean of its divisors is an integer number (636741632086).
Almost surely, 21273483264171 is an apocalyptic number.
1273483264171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1273483264171 is an equidigital number, since it uses as much as digits as its factorization.
1273483264171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1354752, while the sum is 49.
The spelling of 1273483264171 in words is "one trillion, two hundred seventy-three billion, four hundred eighty-three million, two hundred sixty-four thousand, one hundred seventy-one".
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