Base | Representation |
---|---|
bin | 1011100101110100101001… |
… | …1001101101100000011011 |
3 | 1200010100120021112022122102 |
4 | 2321131022121231200123 |
5 | 3132301031023034321 |
6 | 43034412021114015 |
7 | 2453516341335233 |
oct | 271351231554033 |
9 | 50110507468572 |
10 | 12744416221211 |
11 | 407397078a934 |
12 | 1519b5325890b |
13 | 715a40b3150c |
14 | 320b93bcccc3 |
15 | 1717a154ec0b |
hex | b974a66d81b |
12744416221211 has 4 divisors (see below), whose sum is σ = 12744474158424. Its totient is φ = 12744358284000.
The previous prime is 12744416221153. The next prime is 12744416221213. The reversal of 12744416221211 is 11212261444721.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12744416221211 - 210 = 12744416220187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12744416221213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28637390 + ... + 29079011.
It is an arithmetic number, because the mean of its divisors is an integer number (3186118539606).
Almost surely, 212744416221211 is an apocalyptic number.
12744416221211 is a deficient number, since it is larger than the sum of its proper divisors (57937213).
12744416221211 is an equidigital number, since it uses as much as digits as its factorization.
12744416221211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57937212.
The product of its digits is 43008, while the sum is 38.
Adding to 12744416221211 its reverse (11212261444721), we get a palindrome (23956677665932).
The spelling of 12744416221211 in words is "twelve trillion, seven hundred forty-four billion, four hundred sixteen million, two hundred twenty-one thousand, two hundred eleven".
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