12751450641471 has 4 divisors (see below), whose sum is σ = 17001934188632. Its totient is φ = 8500967094312.

The previous prime is 12751450641469. The next prime is 12751450641473. The reversal of 12751450641471 is 17414605415721.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12751450641469) and next prime (12751450641473).

It is not a de Polignac number, because 12751450641471 - 2¹ = 12751450641469 is a prime.

It is a super-3 number, since 3×12751450641471³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12751450641471.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12751450641473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2125241773576 + ... + 2125241773581.

It is an arithmetic number, because the mean of its divisors is an integer number (4250483547158).

Almost surely, 2^{12751450641471} is an apocalyptic number.

12751450641471 is a deficient number, since it is larger than the sum of its proper divisors (4250483547161).

12751450641471 is an equidigital number, since it uses as much as digits as its factorization.

12751450641471 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4250483547160.

The product of its (nonzero) digits is 940800, while the sum is 48.

The spelling of 12751450641471 in words is "twelve trillion, seven hundred fifty-one billion, four hundred fifty million, six hundred forty-one thousand, four hundred seventy-one".