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12753163433 = 61209068253
BaseRepresentation
bin10111110000010010…
…11101010010101001
31012220210022211100102
423320021131102221
5202104302212213
65505252315145
7631015046333
oct137011352251
935823284312
1012753163433
11545491249a
12257b012ab5
1312831c916a
1488da74453
154e9945158
hex2f825d4a9

12753163433 has 4 divisors (see below), whose sum is σ = 12962231748. Its totient is φ = 12544095120.

The previous prime is 12753163429. The next prime is 12753163459. The reversal of 12753163433 is 33436135721.

12753163433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4257301504 + 8495861929 = 65248^2 + 92173^2 .

It is a cyclic number.

It is not a de Polignac number, because 12753163433 - 22 = 12753163429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12753163133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104534066 + ... + 104534187.

It is an arithmetic number, because the mean of its divisors is an integer number (3240557937).

Almost surely, 212753163433 is an apocalyptic number.

It is an amenable number.

12753163433 is a deficient number, since it is larger than the sum of its proper divisors (209068315).

12753163433 is an equidigital number, since it uses as much as digits as its factorization.

12753163433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 209068314.

The product of its digits is 136080, while the sum is 38.

The spelling of 12753163433 in words is "twelve billion, seven hundred fifty-three million, one hundred sixty-three thousand, four hundred thirty-three".

Divisors: 1 61 209068253 12753163433