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12767450428133 is a prime number
BaseRepresentation
bin1011100111001010011101…
…0110001111001011100101
31200012120000120110021022022
42321302213112033023211
53133140214302200013
643053141420112525
72455263216014402
oct271624726171345
950176016407268
1012767450428133
114082710a13485
121522501395745
13717c7200945b
14321d3b0632a9
1517219d86a008
hexb9ca758f2e5

12767450428133 has 2 divisors, whose sum is σ = 12767450428134. Its totient is φ = 12767450428132.

The previous prime is 12767450428093. The next prime is 12767450428151. The reversal of 12767450428133 is 33182405476721.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12756740868964 + 10709559169 = 3571658^2 + 103487^2 .

It is a cyclic number.

It is not a de Polignac number, because 12767450428133 - 218 = 12767450165989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12767450428153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6383725214066 + 6383725214067.

It is an arithmetic number, because the mean of its divisors is an integer number (6383725214067).

Almost surely, 212767450428133 is an apocalyptic number.

It is an amenable number.

12767450428133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12767450428133 is an equidigital number, since it uses as much as digits as its factorization.

12767450428133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6773760, while the sum is 53.

The spelling of 12767450428133 in words is "twelve trillion, seven hundred sixty-seven billion, four hundred fifty million, four hundred twenty-eight thousand, one hundred thirty-three".