Base | Representation |
---|---|
bin | 1011100111001010011101… |
… | …0110001111001011100101 |
3 | 1200012120000120110021022022 |
4 | 2321302213112033023211 |
5 | 3133140214302200013 |
6 | 43053141420112525 |
7 | 2455263216014402 |
oct | 271624726171345 |
9 | 50176016407268 |
10 | 12767450428133 |
11 | 4082710a13485 |
12 | 1522501395745 |
13 | 717c7200945b |
14 | 321d3b0632a9 |
15 | 17219d86a008 |
hex | b9ca758f2e5 |
12767450428133 has 2 divisors, whose sum is σ = 12767450428134. Its totient is φ = 12767450428132.
The previous prime is 12767450428093. The next prime is 12767450428151. The reversal of 12767450428133 is 33182405476721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12756740868964 + 10709559169 = 3571658^2 + 103487^2 .
It is a cyclic number.
It is not a de Polignac number, because 12767450428133 - 218 = 12767450165989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12767450428153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6383725214066 + 6383725214067.
It is an arithmetic number, because the mean of its divisors is an integer number (6383725214067).
Almost surely, 212767450428133 is an apocalyptic number.
It is an amenable number.
12767450428133 is a deficient number, since it is larger than the sum of its proper divisors (1).
12767450428133 is an equidigital number, since it uses as much as digits as its factorization.
12767450428133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6773760, while the sum is 53.
The spelling of 12767450428133 in words is "twelve trillion, seven hundred sixty-seven billion, four hundred fifty million, four hundred twenty-eight thousand, one hundred thirty-three".
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