Base | Representation |
---|---|
bin | 1011100111010111100001… |
… | …0111010000101101011111 |
3 | 1200012220001221221102100211 |
4 | 2321311320113100231133 |
5 | 3133214410011302222 |
6 | 43054521405033251 |
7 | 2455446136355563 |
oct | 271657027205537 |
9 | 50186057842324 |
10 | 12770957134687 |
11 | 4084150400a74 |
12 | 152311b855827 |
13 | 7183b068354b |
14 | 322190a896a3 |
15 | 17230664e277 |
hex | b9d785d0b5f |
12770957134687 has 2 divisors, whose sum is σ = 12770957134688. Its totient is φ = 12770957134686.
The previous prime is 12770957134651. The next prime is 12770957134777. The reversal of 12770957134687 is 78643175907721.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12770957134687 - 211 = 12770957132639 is a prime.
It is a super-2 number, since 2×127709571346872 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12770957134627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6385478567343 + 6385478567344.
It is an arithmetic number, because the mean of its divisors is an integer number (6385478567344).
It is a 1-persistent number, because it is pandigital, but 2⋅12770957134687 = 25541914269374 is not.
Almost surely, 212770957134687 is an apocalyptic number.
12770957134687 is a deficient number, since it is larger than the sum of its proper divisors (1).
12770957134687 is an equidigital number, since it uses as much as digits as its factorization.
12770957134687 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124467840, while the sum is 67.
The spelling of 12770957134687 in words is "twelve trillion, seven hundred seventy billion, nine hundred fifty-seven million, one hundred thirty-four thousand, six hundred eighty-seven".
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