Base | Representation |
---|---|
bin | 1011100111011100010111… |
… | …0001000001101011100111 |
3 | 1200020000102110111010102022 |
4 | 2321313011301001223213 |
5 | 3133230034432001003 |
6 | 43055254314333355 |
7 | 2455523255315066 |
oct | 271670561015347 |
9 | 50200373433368 |
10 | 12772255734503 |
11 | 4084757432261 |
12 | 152342272a25b |
13 | 71855971b0c5 |
14 | 3222753241dd |
15 | 172380664738 |
hex | b9dc5c41ae7 |
12772255734503 has 4 divisors (see below), whose sum is σ = 12772263042240. Its totient is φ = 12772248426768.
The previous prime is 12772255734463. The next prime is 12772255734523. The reversal of 12772255734503 is 30543755227721.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 12772255734503 - 212 = 12772255730407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12772255734523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 686051 + ... + 5100507.
It is an arithmetic number, because the mean of its divisors is an integer number (3193065760560).
Almost surely, 212772255734503 is an apocalyptic number.
12772255734503 is a deficient number, since it is larger than the sum of its proper divisors (7307737).
12772255734503 is an equidigital number, since it uses as much as digits as its factorization.
12772255734503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7307736.
The product of its (nonzero) digits is 12348000, while the sum is 53.
The spelling of 12772255734503 in words is "twelve trillion, seven hundred seventy-two billion, two hundred fifty-five million, seven hundred thirty-four thousand, five hundred three".
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