Base | Representation |
---|---|
bin | 11101000110110010101110… |
… | …010100101100111000100011 |
3 | 121210020122112001110022221221 |
4 | 131012302232110230320203 |
5 | 113234304221231433131 |
6 | 1132131013012555511 |
7 | 35651266232320126 |
oct | 3506625624547043 |
9 | 553218461408857 |
10 | 128010129952291 |
11 | 37873878160544 |
12 | 12435279622b97 |
13 | 56573c390b132 |
14 | 2387a1ac1c3bd |
15 | ebec85a98411 |
hex | 746cae52ce23 |
128010129952291 has 2 divisors, whose sum is σ = 128010129952292. Its totient is φ = 128010129952290.
The previous prime is 128010129952213. The next prime is 128010129952333. The reversal of 128010129952291 is 192259921010821.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 128010129952291 - 29 = 128010129951779 is a prime.
It is a super-2 number, since 2×1280101299522912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (128010129952591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64005064976145 + 64005064976146.
It is an arithmetic number, because the mean of its divisors is an integer number (64005064976146).
Almost surely, 2128010129952291 is an apocalyptic number.
128010129952291 is a deficient number, since it is larger than the sum of its proper divisors (1).
128010129952291 is an equidigital number, since it uses as much as digits as its factorization.
128010129952291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 52.
The spelling of 128010129952291 in words is "one hundred twenty-eight trillion, ten billion, one hundred twenty-nine million, nine hundred fifty-two thousand, two hundred ninety-one".
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