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128010129952591 is a prime number
BaseRepresentation
bin11101000110110010101110…
…010100101100111101001111
3121210020122112001110100101001
4131012302232110230331033
5113234304221231440331
61132131013013001131
735651266232321035
oct3506625624547517
9553218461410331
10128010129952591
1137873878160797
12124352796231a7
1356573c390b303
142387a1ac1c555
15ebec85a98561
hex746cae52cf4f

128010129952591 has 2 divisors, whose sum is σ = 128010129952592. Its totient is φ = 128010129952590.

The previous prime is 128010129952583. The next prime is 128010129952603. The reversal of 128010129952591 is 195259921010821.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 128010129952591 - 23 = 128010129952583 is a prime.

It is a super-2 number, since 2×1280101299525912 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (128010129952501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64005064976295 + 64005064976296.

It is an arithmetic number, because the mean of its divisors is an integer number (64005064976296).

Almost surely, 2128010129952591 is an apocalyptic number.

128010129952591 is a deficient number, since it is larger than the sum of its proper divisors (1).

128010129952591 is an equidigital number, since it uses as much as digits as its factorization.

128010129952591 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1166400, while the sum is 55.

The spelling of 128010129952591 in words is "one hundred twenty-eight trillion, ten billion, one hundred twenty-nine million, nine hundred fifty-two thousand, five hundred ninety-one".