Base | Representation |
---|---|
bin | 111011100111111000… |
… | …1111001010100111011 |
3 | 110020111022212200212211 |
4 | 1313033301321110323 |
5 | 4044211220441123 |
6 | 134453141515551 |
7 | 12151644112564 |
oct | 1671761712473 |
9 | 406438780784 |
10 | 128040015163 |
11 | 4a335283555 |
12 | 20994412bb7 |
13 | c0c6acaba8 |
14 | 62a906916b |
15 | 34e5c5740d |
hex | 1dcfc7953b |
128040015163 has 4 divisors (see below), whose sum is σ = 133606972368. Its totient is φ = 122473057960.
The previous prime is 128040015161. The next prime is 128040015199. The reversal of 128040015163 is 361510040821.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 128040015163 - 21 = 128040015161 is a prime.
It is a super-3 number, since 3×1280400151633 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (128040015161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2783478568 + ... + 2783478613.
It is an arithmetic number, because the mean of its divisors is an integer number (33401743092).
Almost surely, 2128040015163 is an apocalyptic number.
128040015163 is a deficient number, since it is larger than the sum of its proper divisors (5566957205).
128040015163 is an equidigital number, since it uses as much as digits as its factorization.
128040015163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5566957204.
The product of its (nonzero) digits is 5760, while the sum is 31.
Adding to 128040015163 its reverse (361510040821), we get a palindrome (489550055984).
The spelling of 128040015163 in words is "one hundred twenty-eight billion, forty million, fifteen thousand, one hundred sixty-three".
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