Base | Representation |
---|---|
bin | 1011101001010101110000… |
… | …0000010100001111010101 |
3 | 1200100010112101121000020110 |
4 | 2322111130000110033111 |
5 | 3134243303310034044 |
6 | 43122243543553233 |
7 | 2461055620316334 |
oct | 272253400241725 |
9 | 50303471530213 |
10 | 12804841096149 |
11 | 4097558a82803 |
12 | 15297b745b819 |
13 | 71b6505cc29b |
14 | 323a86c7dd1b |
15 | 17313b22b6b9 |
hex | ba55c0143d5 |
12804841096149 has 4 divisors (see below), whose sum is σ = 17073121461536. Its totient is φ = 8536560730764.
The previous prime is 12804841096141. The next prime is 12804841096153. The reversal of 12804841096149 is 94169014840821.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12804841096149 - 23 = 12804841096141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12804841096141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2134140182689 + ... + 2134140182694.
It is an arithmetic number, because the mean of its divisors is an integer number (4268280365384).
Almost surely, 212804841096149 is an apocalyptic number.
It is an amenable number.
12804841096149 is a deficient number, since it is larger than the sum of its proper divisors (4268280365387).
12804841096149 is an equidigital number, since it uses as much as digits as its factorization.
12804841096149 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4268280365386.
The product of its (nonzero) digits is 3981312, while the sum is 57.
The spelling of 12804841096149 in words is "twelve trillion, eight hundred four billion, eight hundred forty-one million, ninety-six thousand, one hundred forty-nine".
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