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128050287403 is a prime number
BaseRepresentation
bin111011101000001100…
…1000101001100101011
3110020112001012120202011
41313100121011030223
54044221333144103
6134454150020351
712152130325033
oct1672031051453
9406461176664
10128050287403
114a34005a205
12209979476b7
13c0c8c8663c
1462aa5808c3
1534e6ad5d6d
hex1dd064532b

128050287403 has 2 divisors, whose sum is σ = 128050287404. Its totient is φ = 128050287402.

The previous prime is 128050287397. The next prime is 128050287439. The reversal of 128050287403 is 304782050821.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 128050287403 - 213 = 128050279211 is a prime.

It is a super-2 number, since 2×1280502874032 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (128050287473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64025143701 + 64025143702.

It is an arithmetic number, because the mean of its divisors is an integer number (64025143702).

Almost surely, 2128050287403 is an apocalyptic number.

128050287403 is a deficient number, since it is larger than the sum of its proper divisors (1).

128050287403 is an equidigital number, since it uses as much as digits as its factorization.

128050287403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 107520, while the sum is 40.

The spelling of 128050287403 in words is "one hundred twenty-eight billion, fifty million, two hundred eighty-seven thousand, four hundred three".