Base | Representation |
---|---|
bin | 1011101001110010001001… |
… | …1010110101000101001011 |
3 | 1200100212012201010111102201 |
4 | 2322130202122311011023 |
5 | 3134404412003334400 |
6 | 43125544244341031 |
7 | 2461445552516050 |
oct | 272344232650513 |
9 | 50325181114381 |
10 | 12812464902475 |
11 | 409a810465297 |
12 | 152b1846a4777 |
13 | 71c296c178a4 |
14 | 3241ab5bd027 |
15 | 1734356b706a |
hex | ba7226b514b |
12812464902475 has 24 divisors (see below), whose sum is σ = 19112729603840. Its totient is φ = 8323285468320.
The previous prime is 12812464902473. The next prime is 12812464902487. The reversal of 12812464902475 is 57420946421821.
12812464902475 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12812464902475 - 21 = 12812464902473 is a prime.
It is a super-2 number, since 2×128124649024752 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12812464902473) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1926683127 + ... + 1926689776.
Almost surely, 212812464902475 is an apocalyptic number.
12812464902475 is a deficient number, since it is larger than the sum of its proper divisors (6300264701365).
12812464902475 is a wasteful number, since it uses less digits than its factorization.
12812464902475 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3853372939 (or 3853372934 counting only the distinct ones).
The product of its (nonzero) digits is 7741440, while the sum is 55.
The spelling of 12812464902475 in words is "twelve trillion, eight hundred twelve billion, four hundred sixty-four million, nine hundred two thousand, four hundred seventy-five".
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