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1281317740301 is a prime number
BaseRepresentation
bin10010101001010100011…
…111010001111100001101
311112111022020101022211202
4102221110133101330031
5131443114320142201
62420343525555245
7161400151043054
oct22512437217415
94474266338752
101281317740301
11454449507a45
121883b2875b25
1393a9b7294c1
14460322c139b
15234e3c00c6b
hex12a547d1f0d

1281317740301 has 2 divisors, whose sum is σ = 1281317740302. Its totient is φ = 1281317740300.

The previous prime is 1281317740267. The next prime is 1281317740321. The reversal of 1281317740301 is 1030477131821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1134808695076 + 146509045225 = 1065274^2 + 382765^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1281317740301 is a prime.

It is a super-2 number, since 2×12813177403012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1281317740321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640658870150 + 640658870151.

It is an arithmetic number, because the mean of its divisors is an integer number (640658870151).

Almost surely, 21281317740301 is an apocalyptic number.

It is an amenable number.

1281317740301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1281317740301 is an equidigital number, since it uses as much as digits as its factorization.

1281317740301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28224, while the sum is 38.

The spelling of 1281317740301 in words is "one trillion, two hundred eighty-one billion, three hundred seventeen million, seven hundred forty thousand, three hundred one".