12814349753 has 4 divisors (see below), whose sum is σ = 12814611600. Its totient is φ = 12814087908.

The previous prime is 12814349659. The next prime is 12814349773. The reversal of 12814349753 is 35794341821.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12814349753 - 2⁸ = 12814349497 is a prime.

It is a super-2 number, since 2×12814349753² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12814349698 and 12814349707.

It is not an unprimeable number, because it can be changed into a prime (12814349773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33203 + ... + 163496.

It is an arithmetic number, because the mean of its divisors is an integer number (3203652900).

Almost surely, 2^12814349753 is an apocalyptic number.

It is an amenable number.

12814349753 is a deficient number, since it is larger than the sum of its proper divisors (261847).

12814349753 is an equidigital number, since it uses as much as digits as its factorization.

12814349753 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261846.

The product of its digits is 725760, while the sum is 47.

The spelling of 12814349753 in words is "twelve billion, eight hundred fourteen million, three hundred forty-nine thousand, seven hundred fifty-three".