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128201196685817 is a prime number
BaseRepresentation
bin11101001001100100101010…
…110010011100100111111001
3121210220220200211020001122002
4131021210222302130213321
5113300422022322421232
61132354452224110345
736001142110623353
oct3511445262344771
9553826624201562
10128201196685817
1137937905370392
12124663014653b5
13566c423243ac8
142392d846da0d3
15ec4c19b23b62
hex74992ac9c9f9

128201196685817 has 2 divisors, whose sum is σ = 128201196685818. Its totient is φ = 128201196685816.

The previous prime is 128201196685813. The next prime is 128201196685819. The reversal of 128201196685817 is 718586691102821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112048385554681 + 16152811131136 = 10585291^2 + 4019056^2 .

It is a cyclic number.

It is not a de Polignac number, because 128201196685817 - 22 = 128201196685813 is a prime.

Together with 128201196685819, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (128201196685811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64100598342908 + 64100598342909.

It is an arithmetic number, because the mean of its divisors is an integer number (64100598342909).

Almost surely, 2128201196685817 is an apocalyptic number.

It is an amenable number.

128201196685817 is a deficient number, since it is larger than the sum of its proper divisors (1).

128201196685817 is an equidigital number, since it uses as much as digits as its factorization.

128201196685817 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23224320, while the sum is 65.

The spelling of 128201196685817 in words is "one hundred twenty-eight trillion, two hundred one billion, one hundred ninety-six million, six hundred eighty-five thousand, eight hundred seventeen".