12825398953 has 2 divisors, whose sum is σ = 12825398954. Its totient is φ = 12825398952.

The previous prime is 12825398921. The next prime is 12825398977. The reversal of 12825398953 is 35989352821.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12802243609 + 23155344 = 113147^2 + 4812^2 .

It is a cyclic number.

It is not a de Polignac number, because 12825398953 - 2⁵ = 12825398921 is a prime.

It is a super-2 number, since 2×12825398953² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12825398894 and 12825398903.

It is not a weakly prime, because it can be changed into another prime (12825398903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6412699476 + 6412699477.

It is an arithmetic number, because the mean of its divisors is an integer number (6412699477).

Almost surely, 2^12825398953 is an apocalyptic number.

It is an amenable number.

12825398953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12825398953 is an equidigital number, since it uses as much as digits as its factorization.

12825398953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4665600, while the sum is 55.

It can be divided in two parts, 12825 and 398953, that added together give a triangular number (411778 = T₉₀₇).

The spelling of 12825398953 in words is "twelve billion, eight hundred twenty-five million, three hundred ninety-eight thousand, nine hundred fifty-three".