Base | Representation |
---|---|
bin | 10111111001101000… |
… | …00101001010010011 |
3 | 1020010020121222100211 |
4 | 23330310011022103 |
5 | 202234322230101 |
6 | 5521130224551 |
7 | 632655326353 |
oct | 137464051223 |
9 | 36106558324 |
10 | 12831445651 |
11 | 5495020042 |
12 | 25a1285157 |
13 | 12964a76bb |
14 | 89a210b63 |
15 | 501759c51 |
hex | 2fcd05293 |
12831445651 has 2 divisors, whose sum is σ = 12831445652. Its totient is φ = 12831445650.
The previous prime is 12831445639. The next prime is 12831445667. The reversal of 12831445651 is 15654413821.
12831445651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12831445651 - 215 = 12831412883 is a prime.
It is not a weakly prime, because it can be changed into another prime (12831445681) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6415722825 + 6415722826.
It is an arithmetic number, because the mean of its divisors is an integer number (6415722826).
Almost surely, 212831445651 is an apocalyptic number.
12831445651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12831445651 is an equidigital number, since it uses as much as digits as its factorization.
12831445651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 115200, while the sum is 40.
The spelling of 12831445651 in words is "twelve billion, eight hundred thirty-one million, four hundred forty-five thousand, six hundred fifty-one".
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