Base | Representation |
---|---|
bin | 10111111010011000… |
… | …01000001110010011 |
3 | 1020010200111020211022 |
4 | 23331030020032103 |
5 | 202242430442101 |
6 | 5521513310055 |
7 | 633063033356 |
oct | 137514101623 |
9 | 36120436738 |
10 | 12837749651 |
11 | 5498636361 |
12 | 25a340532b |
13 | 12978a3b8c |
14 | 89adb229d |
15 | 5020a2a1b |
hex | 2fd308393 |
12837749651 has 2 divisors, whose sum is σ = 12837749652. Its totient is φ = 12837749650.
The previous prime is 12837749599. The next prime is 12837749671. The reversal of 12837749651 is 15694773821.
12837749651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12837749651 is a prime.
It is a super-2 number, since 2×128377496512 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12837749593 and 12837749602.
It is not a weakly prime, because it can be changed into another prime (12837749671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6418874825 + 6418874826.
It is an arithmetic number, because the mean of its divisors is an integer number (6418874826).
Almost surely, 212837749651 is an apocalyptic number.
12837749651 is a deficient number, since it is larger than the sum of its proper divisors (1).
12837749651 is an equidigital number, since it uses as much as digits as its factorization.
12837749651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2540160, while the sum is 53.
The spelling of 12837749651 in words is "twelve billion, eight hundred thirty-seven million, seven hundred forty-nine thousand, six hundred fifty-one".
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