Base | Representation |
---|---|
bin | 10111111011011000… |
… | …11010010001001101 |
3 | 1020011021102012020001 |
4 | 23331230122101031 |
5 | 202302112242143 |
6 | 5522414524301 |
7 | 633225000424 |
oct | 137554322115 |
9 | 36137365201 |
10 | 12846212173 |
11 | 54a2396383 |
12 | 25a6206691 |
13 | 12995779a2 |
14 | 89c1762bb |
15 | 502bc514d |
hex | 2fdb1a44d |
12846212173 has 4 divisors (see below), whose sum is σ = 12846636288. Its totient is φ = 12845788060.
The previous prime is 12846212153. The next prime is 12846212191. The reversal of 12846212173 is 37121264821.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12846212173 - 29 = 12846211661 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12846212123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 162811 + ... + 228472.
It is an arithmetic number, because the mean of its divisors is an integer number (3211659072).
Almost surely, 212846212173 is an apocalyptic number.
It is an amenable number.
12846212173 is a deficient number, since it is larger than the sum of its proper divisors (424115).
12846212173 is an equidigital number, since it uses as much as digits as its factorization.
12846212173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 424114.
The product of its digits is 32256, while the sum is 37.
Adding to 12846212173 its reverse (37121264821), we get a palindrome (49967476994).
The spelling of 12846212173 in words is "twelve billion, eight hundred forty-six million, two hundred twelve thousand, one hundred seventy-three".
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