Base | Representation |
---|---|
bin | 1011101100001111111101… |
… | …0000110000000101001001 |
3 | 1200111220112211121202000221 |
4 | 2323003333100300011021 |
5 | 3141103140112342303 |
6 | 43201231442430041 |
7 | 2464505353232212 |
oct | 273037720600511 |
9 | 50456484552027 |
10 | 12854824730953 |
11 | 41067784883a7 |
12 | 1537426962321 |
13 | 723287b5c15a |
14 | 326269350409 |
15 | 1745b443c4bd |
hex | bb0ff430149 |
12854824730953 has 2 divisors, whose sum is σ = 12854824730954. Its totient is φ = 12854824730952.
The previous prime is 12854824730941. The next prime is 12854824730981. The reversal of 12854824730953 is 35903742845821.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6877254492304 + 5977570238649 = 2622452^2 + 2444907^2 .
It is a cyclic number.
It is not a de Polignac number, because 12854824730953 - 29 = 12854824730441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12854824730891 and 12854824730900.
It is not a weakly prime, because it can be changed into another prime (12854824730933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6427412365476 + 6427412365477.
It is an arithmetic number, because the mean of its divisors is an integer number (6427412365477).
Almost surely, 212854824730953 is an apocalyptic number.
It is an amenable number.
12854824730953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12854824730953 is an equidigital number, since it uses as much as digits as its factorization.
12854824730953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58060800, while the sum is 61.
The spelling of 12854824730953 in words is "twelve trillion, eight hundred fifty-four billion, eight hundred twenty-four million, seven hundred thirty thousand, nine hundred fifty-three".
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