Base | Representation |
---|---|
bin | 10111111101000101… |
… | …01010001011100101 |
3 | 1020012021011200200222 |
4 | 23332202222023211 |
5 | 202314232330000 |
6 | 5524043414125 |
7 | 633456610061 |
oct | 137642521345 |
9 | 36167150628 |
10 | 12860433125 |
11 | 54aa419831 |
12 | 25aab24345 |
13 | 129c4b6857 |
14 | 89ddd8aa1 |
15 | 504083a85 |
hex | 2fe8aa2e5 |
12860433125 has 40 divisors (see below), whose sum is σ = 16296783360. Its totient is φ = 10144440000.
The previous prime is 12860433083. The next prime is 12860433127. The reversal of 12860433125 is 52133406821.
It is not a de Polignac number, because 12860433125 - 28 = 12860432869 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12860433127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 21186572 + ... + 21187178.
It is an arithmetic number, because the mean of its divisors is an integer number (407419584).
Almost surely, 212860433125 is an apocalyptic number.
It is an amenable number.
12860433125 is a deficient number, since it is larger than the sum of its proper divisors (3436350235).
12860433125 is an equidigital number, since it uses as much as digits as its factorization.
12860433125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1047 (or 1032 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 35.
Adding to 12860433125 its reverse (52133406821), we get a palindrome (64993839946).
The spelling of 12860433125 in words is "twelve billion, eight hundred sixty million, four hundred thirty-three thousand, one hundred twenty-five".
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