Base | Representation |
---|---|
bin | 10010101110101111110… |
… | …101100101111001100101 |
3 | 11120001100100221011210221 |
4 | 102232233311211321211 |
5 | 132042033143030143 |
6 | 2423150102244341 |
7 | 161664442250011 |
oct | 22565765457145 |
9 | 4501310834727 |
10 | 1287145283173 |
11 | 456969a58182 |
12 | 18955a4266b1 |
13 | 944b9b62719 |
14 | 4642623b541 |
15 | 237356202ed |
hex | 12bafd65e65 |
1287145283173 has 2 divisors, whose sum is σ = 1287145283174. Its totient is φ = 1287145283172.
The previous prime is 1287145283159. The next prime is 1287145283183. The reversal of 1287145283173 is 3713825417821.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1184653742724 + 102491540449 = 1088418^2 + 320143^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1287145283173 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1287145283173.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1287145283183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 643572641586 + 643572641587.
It is an arithmetic number, because the mean of its divisors is an integer number (643572641587).
Almost surely, 21287145283173 is an apocalyptic number.
It is an amenable number.
1287145283173 is a deficient number, since it is larger than the sum of its proper divisors (1).
1287145283173 is an equidigital number, since it uses as much as digits as its factorization.
1287145283173 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2257920, while the sum is 52.
The spelling of 1287145283173 in words is "one trillion, two hundred eighty-seven billion, one hundred forty-five million, two hundred eighty-three thousand, one hundred seventy-three".
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