Base | Representation |
---|---|
bin | 10111111111101011… |
… | …11000100011110011 |
3 | 1020020210020002210022 |
4 | 23333311320203303 |
5 | 202340323444341 |
6 | 5530143154055 |
7 | 634143214043 |
oct | 137765704363 |
9 | 36223202708 |
10 | 12882249971 |
11 | 5510770088 |
12 | 25b62a592b |
13 | 12a3b84c26 |
14 | 8a2c77723 |
15 | 505e42e4b |
hex | 2ffd788f3 |
12882249971 has 2 divisors, whose sum is σ = 12882249972. Its totient is φ = 12882249970.
The previous prime is 12882249943. The next prime is 12882250001. The reversal of 12882249971 is 17994228821.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12882249971 - 210 = 12882248947 is a prime.
It is not a weakly prime, because it can be changed into another prime (12882249871) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6441124985 + 6441124986.
It is an arithmetic number, because the mean of its divisors is an integer number (6441124986).
Almost surely, 212882249971 is an apocalyptic number.
12882249971 is a deficient number, since it is larger than the sum of its proper divisors (1).
12882249971 is an equidigital number, since it uses as much as digits as its factorization.
12882249971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1161216, while the sum is 53.
The spelling of 12882249971 in words is "twelve billion, eight hundred eighty-two million, two hundred forty-nine thousand, nine hundred seventy-one".
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