Base | Representation |
---|---|
bin | 1011101110000011111001… |
… | …0100110101000011110010 |
3 | 1200121212212211200000211102 |
4 | 2323200332110311003302 |
5 | 3142110410032114402 |
6 | 43223420024244402 |
7 | 2466656535554051 |
oct | 273407624650362 |
9 | 50555784600742 |
10 | 12885947535602 |
11 | 41189994a2159 |
12 | 1541471910702 |
13 | 7261a7a2aaab |
14 | 32797c952398 |
15 | 1752d6904102 |
hex | bb83e5350f2 |
12885947535602 has 4 divisors (see below), whose sum is σ = 19328921303406. Its totient is φ = 6442973767800.
The previous prime is 12885947535599. The next prime is 12885947535623. The reversal of 12885947535602 is 20653574958821.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8246666633401 + 4639280902201 = 2871701^2 + 2153899^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3221486883899 + ... + 3221486883902.
It is a 1-persistent number, because it is pandigital, but 2⋅12885947535602 = 25771895071204 is not.
Almost surely, 212885947535602 is an apocalyptic number.
12885947535602 is a deficient number, since it is larger than the sum of its proper divisors (6442973767804).
12885947535602 is an equidigital number, since it uses as much as digits as its factorization.
12885947535602 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6442973767803.
The product of its (nonzero) digits is 145152000, while the sum is 65.
The spelling of 12885947535602 in words is "twelve trillion, eight hundred eighty-five billion, nine hundred forty-seven million, five hundred thirty-five thousand, six hundred two".
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