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128879564713 is a prime number
BaseRepresentation
bin111100000000111010…
…0100001011110101001
3110022122211122020100121
41320001310201132221
54102421132032323
6135112332203241
712211520140114
oct1700164413651
9408584566317
10128879564713
114a726177559
1220b89609521
13c1cba1a583
14634876b57b
1535447e2a5d
hex1e01d217a9

128879564713 has 2 divisors, whose sum is σ = 128879564714. Its totient is φ = 128879564712.

The previous prime is 128879564699. The next prime is 128879564717. The reversal of 128879564713 is 317465978821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126937576089 + 1941988624 = 356283^2 + 44068^2 .

It is an emirp because it is prime and its reverse (317465978821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 128879564713 - 233 = 120289630121 is a prime.

It is a super-2 number, since 2×1288795647132 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (128879564717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64439782356 + 64439782357.

It is an arithmetic number, because the mean of its divisors is an integer number (64439782357).

Almost surely, 2128879564713 is an apocalyptic number.

It is an amenable number.

128879564713 is a deficient number, since it is larger than the sum of its proper divisors (1).

128879564713 is an equidigital number, since it uses as much as digits as its factorization.

128879564713 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20321280, while the sum is 61.

The spelling of 128879564713 in words is "one hundred twenty-eight billion, eight hundred seventy-nine million, five hundred sixty-four thousand, seven hundred thirteen".