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12894050283 = 34298016761
BaseRepresentation
bin11000000001000101…
…11001011111101011
31020021121102121202220
430000202321133223
5202401334102113
65531244125123
7634345422222
oct140042713753
936247377686
1012894050283
11551739a904
1225ba2367a3
1312a645706a
148a4669cb9
15506ec4523
hex3008b97eb

12894050283 has 4 divisors (see below), whose sum is σ = 17192067048. Its totient is φ = 8596033520.

The previous prime is 12894050269. The next prime is 12894050287. The reversal of 12894050283 is 38205049821.

12894050283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12894050283 - 218 = 12893788139 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12894050287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2149008378 + ... + 2149008383.

It is an arithmetic number, because the mean of its divisors is an integer number (4298016762).

Almost surely, 212894050283 is an apocalyptic number.

12894050283 is a deficient number, since it is larger than the sum of its proper divisors (4298016765).

12894050283 is an equidigital number, since it uses as much as digits as its factorization.

12894050283 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4298016764.

The product of its (nonzero) digits is 138240, while the sum is 42.

The spelling of 12894050283 in words is "twelve billion, eight hundred ninety-four million, fifty thousand, two hundred eighty-three".

Divisors: 1 3 4298016761 12894050283